Optimal. Leaf size=142 \[ \frac{B d i \text{PolyLog}\left (2,\frac{b (c+d x)}{d (a+b x)}\right )}{b^2 g^2}-\frac{d i \log \left (1-\frac{b (c+d x)}{d (a+b x)}\right ) \left (B \log \left (\frac{e (a+b x)}{c+d x}\right )+A\right )}{b^2 g^2}-\frac{i (c+d x) \left (B \log \left (\frac{e (a+b x)}{c+d x}\right )+A\right )}{b g^2 (a+b x)}-\frac{B i (c+d x)}{b g^2 (a+b x)} \]
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Rubi [A] time = 0.383937, antiderivative size = 221, normalized size of antiderivative = 1.56, number of steps used = 15, number of rules used = 11, integrand size = 38, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.29, Rules used = {2528, 2525, 12, 44, 2524, 2418, 2390, 2301, 2394, 2393, 2391} \[ \frac{B d i \text{PolyLog}\left (2,-\frac{d (a+b x)}{b c-a d}\right )}{b^2 g^2}+\frac{d i \log (a+b x) \left (B \log \left (\frac{e (a+b x)}{c+d x}\right )+A\right )}{b^2 g^2}-\frac{i (b c-a d) \left (B \log \left (\frac{e (a+b x)}{c+d x}\right )+A\right )}{b^2 g^2 (a+b x)}-\frac{B i (b c-a d)}{b^2 g^2 (a+b x)}+\frac{B d i \log (a+b x) \log \left (\frac{b (c+d x)}{b c-a d}\right )}{b^2 g^2}-\frac{B d i \log ^2(a+b x)}{2 b^2 g^2}-\frac{B d i \log (a+b x)}{b^2 g^2}+\frac{B d i \log (c+d x)}{b^2 g^2} \]
Antiderivative was successfully verified.
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Rule 2528
Rule 2525
Rule 12
Rule 44
Rule 2524
Rule 2418
Rule 2390
Rule 2301
Rule 2394
Rule 2393
Rule 2391
Rubi steps
\begin{align*} \int \frac{(6 c+6 d x) \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right )}{(a g+b g x)^2} \, dx &=\int \left (\frac{6 (b c-a d) \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right )}{b g^2 (a+b x)^2}+\frac{6 d \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right )}{b g^2 (a+b x)}\right ) \, dx\\ &=\frac{(6 d) \int \frac{A+B \log \left (\frac{e (a+b x)}{c+d x}\right )}{a+b x} \, dx}{b g^2}+\frac{(6 (b c-a d)) \int \frac{A+B \log \left (\frac{e (a+b x)}{c+d x}\right )}{(a+b x)^2} \, dx}{b g^2}\\ &=-\frac{6 (b c-a d) \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right )}{b^2 g^2 (a+b x)}+\frac{6 d \log (a+b x) \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right )}{b^2 g^2}-\frac{(6 B d) \int \frac{(c+d x) \left (-\frac{d e (a+b x)}{(c+d x)^2}+\frac{b e}{c+d x}\right ) \log (a+b x)}{e (a+b x)} \, dx}{b^2 g^2}+\frac{(6 B (b c-a d)) \int \frac{b c-a d}{(a+b x)^2 (c+d x)} \, dx}{b^2 g^2}\\ &=-\frac{6 (b c-a d) \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right )}{b^2 g^2 (a+b x)}+\frac{6 d \log (a+b x) \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right )}{b^2 g^2}+\frac{\left (6 B (b c-a d)^2\right ) \int \frac{1}{(a+b x)^2 (c+d x)} \, dx}{b^2 g^2}-\frac{(6 B d) \int \frac{(c+d x) \left (-\frac{d e (a+b x)}{(c+d x)^2}+\frac{b e}{c+d x}\right ) \log (a+b x)}{a+b x} \, dx}{b^2 e g^2}\\ &=-\frac{6 (b c-a d) \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right )}{b^2 g^2 (a+b x)}+\frac{6 d \log (a+b x) \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right )}{b^2 g^2}+\frac{\left (6 B (b c-a d)^2\right ) \int \left (\frac{b}{(b c-a d) (a+b x)^2}-\frac{b d}{(b c-a d)^2 (a+b x)}+\frac{d^2}{(b c-a d)^2 (c+d x)}\right ) \, dx}{b^2 g^2}-\frac{(6 B d) \int \left (\frac{b e \log (a+b x)}{a+b x}-\frac{d e \log (a+b x)}{c+d x}\right ) \, dx}{b^2 e g^2}\\ &=-\frac{6 B (b c-a d)}{b^2 g^2 (a+b x)}-\frac{6 B d \log (a+b x)}{b^2 g^2}-\frac{6 (b c-a d) \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right )}{b^2 g^2 (a+b x)}+\frac{6 d \log (a+b x) \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right )}{b^2 g^2}+\frac{6 B d \log (c+d x)}{b^2 g^2}-\frac{(6 B d) \int \frac{\log (a+b x)}{a+b x} \, dx}{b g^2}+\frac{\left (6 B d^2\right ) \int \frac{\log (a+b x)}{c+d x} \, dx}{b^2 g^2}\\ &=-\frac{6 B (b c-a d)}{b^2 g^2 (a+b x)}-\frac{6 B d \log (a+b x)}{b^2 g^2}-\frac{6 (b c-a d) \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right )}{b^2 g^2 (a+b x)}+\frac{6 d \log (a+b x) \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right )}{b^2 g^2}+\frac{6 B d \log (c+d x)}{b^2 g^2}+\frac{6 B d \log (a+b x) \log \left (\frac{b (c+d x)}{b c-a d}\right )}{b^2 g^2}-\frac{(6 B d) \operatorname{Subst}\left (\int \frac{\log (x)}{x} \, dx,x,a+b x\right )}{b^2 g^2}-\frac{(6 B d) \int \frac{\log \left (\frac{b (c+d x)}{b c-a d}\right )}{a+b x} \, dx}{b g^2}\\ &=-\frac{6 B (b c-a d)}{b^2 g^2 (a+b x)}-\frac{6 B d \log (a+b x)}{b^2 g^2}-\frac{3 B d \log ^2(a+b x)}{b^2 g^2}-\frac{6 (b c-a d) \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right )}{b^2 g^2 (a+b x)}+\frac{6 d \log (a+b x) \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right )}{b^2 g^2}+\frac{6 B d \log (c+d x)}{b^2 g^2}+\frac{6 B d \log (a+b x) \log \left (\frac{b (c+d x)}{b c-a d}\right )}{b^2 g^2}-\frac{(6 B d) \operatorname{Subst}\left (\int \frac{\log \left (1+\frac{d x}{b c-a d}\right )}{x} \, dx,x,a+b x\right )}{b^2 g^2}\\ &=-\frac{6 B (b c-a d)}{b^2 g^2 (a+b x)}-\frac{6 B d \log (a+b x)}{b^2 g^2}-\frac{3 B d \log ^2(a+b x)}{b^2 g^2}-\frac{6 (b c-a d) \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right )}{b^2 g^2 (a+b x)}+\frac{6 d \log (a+b x) \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right )}{b^2 g^2}+\frac{6 B d \log (c+d x)}{b^2 g^2}+\frac{6 B d \log (a+b x) \log \left (\frac{b (c+d x)}{b c-a d}\right )}{b^2 g^2}+\frac{6 B d \text{Li}_2\left (-\frac{d (a+b x)}{b c-a d}\right )}{b^2 g^2}\\ \end{align*}
Mathematica [A] time = 0.157152, size = 175, normalized size = 1.23 \[ \frac{i \left (2 B d (a+b x) \text{PolyLog}\left (2,\frac{d (a+b x)}{a d-b c}\right )+2 d (a+b x) \log (a+b x) \left (B \log \left (\frac{e (a+b x)}{c+d x}\right )+B \log \left (\frac{b (c+d x)}{b c-a d}\right )+A-B\right )-2 (A+B) (b c-a d)+2 (a B d-b B c) \log \left (\frac{e (a+b x)}{c+d x}\right )+2 B d (a+b x) \log (c+d x)-B d (a+b x) \log ^2(a+b x)\right )}{2 b^2 g^2 (a+b x)} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.097, size = 1025, normalized size = 7.2 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} -B d i{\left (\frac{{\left ({\left (b x + a\right )} \log \left (b x + a\right ) + a\right )} \log \left (d x + c\right )}{b^{3} g^{2} x + a b^{2} g^{2}} - \int \frac{b^{2} d x^{2} \log \left (e\right ) + a^{2} d +{\left (b^{2} c \log \left (e\right ) + a b d\right )} x +{\left (2 \, b^{2} d x^{2} + a^{2} d +{\left (b^{2} c + 2 \, a b d\right )} x\right )} \log \left (b x + a\right )}{b^{4} d g^{2} x^{3} + a^{2} b^{2} c g^{2} +{\left (b^{4} c g^{2} + 2 \, a b^{3} d g^{2}\right )} x^{2} +{\left (2 \, a b^{3} c g^{2} + a^{2} b^{2} d g^{2}\right )} x}\,{d x}\right )} + A d i{\left (\frac{a}{b^{3} g^{2} x + a b^{2} g^{2}} + \frac{\log \left (b x + a\right )}{b^{2} g^{2}}\right )} - B c i{\left (\frac{\log \left (\frac{b e x}{d x + c} + \frac{a e}{d x + c}\right )}{b^{2} g^{2} x + a b g^{2}} + \frac{1}{b^{2} g^{2} x + a b g^{2}} + \frac{d \log \left (b x + a\right )}{{\left (b^{2} c - a b d\right )} g^{2}} - \frac{d \log \left (d x + c\right )}{{\left (b^{2} c - a b d\right )} g^{2}}\right )} - \frac{A c i}{b^{2} g^{2} x + a b g^{2}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{A d i x + A c i +{\left (B d i x + B c i\right )} \log \left (\frac{b e x + a e}{d x + c}\right )}{b^{2} g^{2} x^{2} + 2 \, a b g^{2} x + a^{2} g^{2}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (d i x + c i\right )}{\left (B \log \left (\frac{{\left (b x + a\right )} e}{d x + c}\right ) + A\right )}}{{\left (b g x + a g\right )}^{2}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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